z+32=2z+28

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Solution for z+32=2z+28 equation: 



z+32=2z+28

We move all terms to the left:

z+32-(2z+28)=0

We get rid of parentheses

z-2z-28+32=0

We add all the numbers together, and all the variables

-1z+4=0

We move all terms containing z to the left, all other terms to the right

-z=-4

z=-4/-1

z=+4

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