z+3z-3z+4z-4z=16

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Solution for z+3z-3z+4z-4z=16 equation: 



z+3z-3z+4z-4z=16

We move all terms to the left:

z+3z-3z+4z-4z-(16)=0

We add all the numbers together, and all the variables

z-16=0

We move all terms containing z to the left, all other terms to the right

z=16

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