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z+4/z=-5
We move all terms to the left:
z+4/z-(-5)=0
Domain of the equation: z!=0We add all the numbers together, and all the variables
z∈R
z+4/z+5=0
We multiply all the terms by the denominator
z*z+5*z+4=0
We add all the numbers together, and all the variables
5z+z*z+4=0
Wy multiply elements
z^2+5z+4=0
a = 1; b = 5; c = +4;
Δ = b2-4ac
Δ = 52-4·1·4
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3}{2*1}=\frac{-8}{2} =-4 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3}{2*1}=\frac{-2}{2} =-1 $
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