z+41=4z+29

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Solution for z+41=4z+29 equation: 



z+41=4z+29

We move all terms to the left:

z+41-(4z+29)=0

We get rid of parentheses

z-4z-29+41=0

We add all the numbers together, and all the variables

-3z+12=0

We move all terms containing z to the left, all other terms to the right

-3z=-12

z=-12/-3

z=+4

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