z+4z+z-4z-2=12

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Solution for z+4z+z-4z-2=12 equation: 



z+4z+z-4z-2=12

We move all terms to the left:

z+4z+z-4z-2-(12)=0

We add all the numbers together, and all the variables

2z-14=0

We move all terms containing z to the left, all other terms to the right

2z=14

z=14/2

z=7

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