z+80-46=10-2z+42

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Solution for z+80-46=10-2z+42 equation: 



z+80-46=10-2z+42

We move all terms to the left:

z+80-46-(10-2z+42)=0

We add all the numbers together, and all the variables

z-(-2z+52)+80-46=0

We add all the numbers together, and all the variables

z-(-2z+52)+34=0

We get rid of parentheses

z+2z-52+34=0

We add all the numbers together, and all the variables

3z-18=0

We move all terms containing z to the left, all other terms to the right

3z=18

z=18/3

z=6

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