z-(9z+26)=4(z+3)

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Solution for z-(9z+26)=4(z+3) equation: 



z-(9z+26)=4(z+3)

We move all terms to the left:

z-(9z+26)-(4(z+3))=0

We get rid of parentheses

z-9z-(4(z+3))-26=0



We calculate terms in parentheses: -(4(z+3)), so:

4(z+3)

We multiply parentheses

4z+12

Back to the equation:

-(4z+12)



We add all the numbers together, and all the variables

-8z-(4z+12)-26=0

We get rid of parentheses

-8z-4z-12-26=0

We add all the numbers together, and all the variables

-12z-38=0

We move all terms containing z to the left, all other terms to the right

-12z=38

z=38/-12

z=-3+1/6

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