z-10(z+1)=8(2-3z)+1

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Solution for z-10(z+1)=8(2-3z)+1 equation: 



z-10(z+1)=8(2-3z)+1

We move all terms to the left:

z-10(z+1)-(8(2-3z)+1)=0

We add all the numbers together, and all the variables

z-10(z+1)-(8(-3z+2)+1)=0

We multiply parentheses

z-10z-(8(-3z+2)+1)-10=0



We calculate terms in parentheses: -(8(-3z+2)+1), so:

8(-3z+2)+1

We multiply parentheses

-24z+16+1

We add all the numbers together, and all the variables

-24z+17

Back to the equation:

-(-24z+17)



We add all the numbers together, and all the variables

-9z-(-24z+17)-10=0

We get rid of parentheses

-9z+24z-17-10=0

We add all the numbers together, and all the variables

15z-27=0

We move all terms containing z to the left, all other terms to the right

15z=27

z=27/15

z=1+4/5

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