z-22=3(3z+11)-z

Solution for z-22=3(3z+11)-z equation:

z-22=3(3z+11)-z

We move all terms to the left:

z-22-(3(3z+11)-z)=0


We calculate terms in parentheses: -(3(3z+11)-z), so:

3(3z+11)-z

We add all the numbers together, and all the variables

-1z+3(3z+11)

We multiply parentheses

-1z+9z+33

We add all the numbers together, and all the variables

8z+33

Back to the equation:

-(8z+33)


We get rid of parentheses

z-8z-33-22=0

We add all the numbers together, and all the variables

-7z-55=0

We move all terms containing z to the left, all other terms to the right

-7z=55

z=55/-7

z=-7+6/7