z-4(z+2)=3(z-4)-2z

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Solution for z-4(z+2)=3(z-4)-2z equation:


Simplifying
z + -4(z + 2) = 3(z + -4) + -2z

Reorder the terms:
z + -4(2 + z) = 3(z + -4) + -2z
z + (2 * -4 + z * -4) = 3(z + -4) + -2z
z + (-8 + -4z) = 3(z + -4) + -2z

Reorder the terms:
-8 + z + -4z = 3(z + -4) + -2z

Combine like terms: z + -4z = -3z
-8 + -3z = 3(z + -4) + -2z

Reorder the terms:
-8 + -3z = 3(-4 + z) + -2z
-8 + -3z = (-4 * 3 + z * 3) + -2z
-8 + -3z = (-12 + 3z) + -2z

Combine like terms: 3z + -2z = 1z
-8 + -3z = -12 + 1z

Solving
-8 + -3z = -12 + 1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-8 + -3z + -1z = -12 + 1z + -1z

Combine like terms: -3z + -1z = -4z
-8 + -4z = -12 + 1z + -1z

Combine like terms: 1z + -1z = 0
-8 + -4z = -12 + 0
-8 + -4z = -12

Add '8' to each side of the equation.
-8 + 8 + -4z = -12 + 8

Combine like terms: -8 + 8 = 0
0 + -4z = -12 + 8
-4z = -12 + 8

Combine like terms: -12 + 8 = -4
-4z = -4

Divide each side by '-4'.
z = 1

Simplifying
z = 1

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