z/(z-1)=1/(z-1)+2

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Solution for z/(z-1)=1/(z-1)+2 equation: 


D( z )

z-1 = 0

z-1 = 0

z-1 = 0

z-1 = 0 // + 1

z = 1

z in (-oo:1) U (1:+oo)

z/(z-1) = 1/(z-1)+2 // - 1/(z-1)+2

z/(z-1)-(1/(z-1))-2 = 0

z/(z-1)-(z-1)^-1-2 = 0

z/(z-1)-1/(z-1)-2 = 0

z/(z-1)-1/(z-1)+(-2*(z-1))/(z-1) = 0

z-2*(z-1)-1 = 0

z-2*z-1+2 = 0

1-z = 0

(1-z)/(z-1) = 0

(1-z)/(z-1) = 0 // * z-1

1-z = 0

1-z = 0 // - 1

-z = -1 // * -1

z = 1

z in { 1} 

z belongs to the empty set

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