z/16=2(3z+1)/9

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Solution for z/16=2(3z+1)/9 equation: 



z/16=2(3z+1)/9

We move all terms to the left:

z/16-(2(3z+1)/9)=0

We calculate fractions


9z^2/()+(-(2(3z+1)*16)/()=0



We calculate terms in parentheses: +(-(2(3z+1)*16)/(), so:

-(2(3z+1)*16)/(

We multiply all the terms by the denominator


-(2(3z+1)*16)



We calculate terms in parentheses: -(2(3z+1)*16), so:

2(3z+1)*16

We multiply parentheses

96z+32

Back to the equation:

-(96z+32)



We get rid of parentheses

-96z-32

Back to the equation:

+(-96z-32)



We get rid of parentheses

9z^2/()-96z-32=0

We multiply all the terms by the denominator


9z^2-96z*()-32*()=0

We add all the numbers together, and all the variables

9z^2-96z*()=0

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