z/2=1/5(z+20

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Solution for z/2=1/5(z+20 equation: 



z/2=1/5(z+20

We move all terms to the left:

z/2-(1/5(z+20)=0



Domain of the equation: 5(z+20)!=0

z∈R



We calculate fractions


(5z^2z/(10zz+()/(10zz=0

We can not solve this equation

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