z/6+33=2z

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Solution for z/6+33=2z equation:



z/6+33=2z
We move all terms to the left:
z/6+33-(2z)=0
We add all the numbers together, and all the variables
-2z+z/6+33=0
We multiply all the terms by the denominator
-2z*6+z+33*6=0
We add all the numbers together, and all the variables
z-2z*6+198=0
Wy multiply elements
z-12z+198=0
We add all the numbers together, and all the variables
-11z+198=0
We move all terms containing z to the left, all other terms to the right
-11z=-198
z=-198/-11
z=+18

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