If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2*x+1)/(x^3+4*x^2+4*x) <= 0;x
x
1;256;1;64;0;0
(2)^(6)
7;3
(2)^(8)
| 8x^2-5x-30=0 | | 3cos^2x-7cosx-2=0 | | %/100=x/y | | 5(4x-3)=1 | | 36/2x=18 | | 2.99/15= | | 7-5r+3r=2r-9 | | 7x+(x+x)=180 | | 3-4x=5x-15 | | (2x+3)(4x^2+3)=-19 | | X+5=8X-3 | | x-2y+z+4=0 | | 8x-3y=85 | | 8x+3y=85 | | X^2+ax-a*2=0 | | x^2+x-2=-0.25x^2+x+3 | | 3x1/4x2/3= | | 2(-4x-6)+2(x+1)=2 | | 4(x-10)=2x+30 | | 4+8=61 | | -(2x+36)=8(x+10) | | 5+(4g-7)=g | | n(n+1)=420 | | 0.4x18/(0.9)=8 | | -2(2t+10)=-40 | | m(m+1)=420 | | m(m+1)=210 | | 8(3s+4)=56 | | 2x(2x+1)=105 | | x(x+1)=105 | | x^9+4x+2=-2 | | In(x*x+X+1)=0 |