z/7=4z/35z+2

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Solution for z/7=4z/35z+2 equation:


z in (-oo:+oo)

z/7 = ((4*z)/35)*z+2 // - ((4*z)/35)*z+2

z/7-(((4*z)/35)*z)-2 = 0

(-4/35)*z^2+z/7-2 = 0

1/7*z-4/35*z^2-2 = 0

DELTA = (1/7)^2-(-2*(-4/35)*4)

DELTA = -219/245

DELTA < 0

z belongs to the empty set

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