z2+-1000z+60775=0

Solution for z2+-1000z+60775=0 equation:

z2+-1000z+60775=0

We add all the numbers together, and all the variables

z^2-1000z=0

a = 1; b = -1000; c = 0;
Δ = b2-4ac
Δ = -10002-4·1·0
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1000000}=1000$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1000)-1000}{2*1}=\frac{0}{2}
=0
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1000)+1000}{2*1}=\frac{2000}{2}
=1000
$