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z2+-1=0
We add all the numbers together, and all the variables
z^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{0}{2}=0$
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