z2+11z+4=0

Solution for z2+11z+4=0 equation:

z2+11z+4=0

We add all the numbers together, and all the variables

z^2+11z+4=0

a = 1; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·1·4
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{105}}{2*1}=\frac{-11-\sqrt{105}}{2}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{105}}{2*1}=\frac{-11+\sqrt{105}}{2}
$