z2+11z+9=5z

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Solution for z2+11z+9=5z equation: 



z2+11z+9=5z

We move all terms to the left:

z2+11z+9-(5z)=0

We add all the numbers together, and all the variables

z^2+6z+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{-6}{2}=-3$

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