z2+2z+2=(-1-2)2=

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Solution for z2+2z+2=(-1-2)2= equation: 



z2+2z+2=(-1-2)2=

We move all terms to the left:

z2+2z+2-((-1-2)2)=0

We add all the numbers together, and all the variables

z2+2z+2-((-3)2)=0

We add all the numbers together, and all the variables

z^2+2z+8=0

a = 1; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation

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