z2+35=12z-1

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Solution for z2+35=12z-1 equation: 



z2+35=12z-1

We move all terms to the left:

z2+35-(12z-1)=0

We add all the numbers together, and all the variables

z^2-(12z-1)+35=0

We get rid of parentheses

z^2-12z+1+35=0

We add all the numbers together, and all the variables

z^2-12z+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{12}{2}=6$

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