If it's not what You are looking for type in the equation solver your own equation and let us solve it.
z2=47
We move all terms to the left:
z2-(47)=0
We add all the numbers together, and all the variables
z^2-47=0
a = 1; b = 0; c = -47;
Δ = b2-4ac
Δ = 02-4·1·(-47)
Δ = 188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{188}=\sqrt{4*47}=\sqrt{4}*\sqrt{47}=2\sqrt{47}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{47}}{2*1}=\frac{0-2\sqrt{47}}{2} =-\frac{2\sqrt{47}}{2} =-\sqrt{47} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{47}}{2*1}=\frac{0+2\sqrt{47}}{2} =\frac{2\sqrt{47}}{2} =\sqrt{47} $
| 19+1=-4(3x-5) | | 14=-3+n | | 4x-33x+4=89 | | -33=34+p)-15 | | (1/3)(6x+3)=2x–5 | | 5=r/13 | | 4(x-1)^2=4 | | 1/2(2x-4)=1/4(4x-4) | | 4(-p-6)=16 | | q+7.5=8.5 | | 6y–5=–3(2y+1) | | -91=13p | | X4x-33x+4=89 | | j-6=20 | | 9x=4x+1 | | 5h+6/5=2 | | -12(x-1=(x+24) | | 12-x^2=-13 | | 9x+5=2x+13 | | -5(x-1)+1=-(x+2) | | -12(x-1)=x+24 | | 5(x-1)+1=-(x+2) | | 24r=288 | | 24y=192 | | 18+v=24 | | -1.1=b/2+-2 | | z^2-14z+49=-81 | | 4.2=r/3 | | 5*h+6/5=2 | | 2x-(x-4)=-(x+8) | | 3.75+d=11.20 | | 3(x-6)^2-18=9 |