z=(120-135)/15=1

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Solution for z=(120-135)/15=1 equation: 



z=(120-135)/15=1

We move all terms to the left:

z-((120-135)/15)=0

We add all the numbers together, and all the variables

z-((-15)/15)=0

We multiply all the terms by the denominator


z*15)-((-15)=0

Wy multiply elements

15z^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{30}=0$

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