z=(6-z)/(3-z)

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Solution for z=(6-z)/(3-z) equation: 



z=(6-z)/(3-z)

We move all terms to the left:

z-((6-z)/(3-z))=0



Domain of the equation: (3-z))!=0

We move all terms containing z to the left, all other terms to the right

-z)!=-3

z!=-3/1

z!=-3

z∈R



We add all the numbers together, and all the variables

z-((-1z+6)/(-1z+3))=0

We multiply all the terms by the denominator


z*(-1z+3))-((-1z+6)=0

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