z=(z+10)+(3z+21)+(z+35)

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Solution for z=(z+10)+(3z+21)+(z+35) equation: 



z=(z+10)+(3z+21)+(z+35)

We move all terms to the left:

z-((z+10)+(3z+21)+(z+35))=0



We calculate terms in parentheses: -((z+10)+(3z+21)+(z+35)), so:

(z+10)+(3z+21)+(z+35)

We get rid of parentheses

z+3z+z+10+21+35

We add all the numbers together, and all the variables

5z+66

Back to the equation:

-(5z+66)



We get rid of parentheses

z-5z-66=0

We add all the numbers together, and all the variables

-4z-66=0

We move all terms containing z to the left, all other terms to the right

-4z=66

z=66/-4

z=-16+1/2

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