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z=-1.84z^2=
We move all terms to the left:
z-(-1.84z^2)=0
We get rid of parentheses
1.84z^2+z=0
a = 1.84; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·1.84·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*1.84}=\frac{-2}{3.68} =-2/3.68 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*1.84}=\frac{0}{3.68} =0 $
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