z=-5;2(5-2z)=20-2(z-1)

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Solution for z=-5;2(5-2z)=20-2(z-1) equation: 



z=-52(5-2z)=20-2(z-1)

We move all terms to the left:

z-(-52(5-2z))=0

We add all the numbers together, and all the variables

z-(-52(-2z+5))=0



We calculate terms in parentheses: -(-52(-2z+5)), so:

-52(-2z+5)

We multiply parentheses

104z-260

Back to the equation:

-(104z-260)



We get rid of parentheses

z-104z+260=0

We add all the numbers together, and all the variables

-103z+260=0

We move all terms containing z to the left, all other terms to the right

-103z=-260

z=-260/-103

z=2+54/103

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