z=0.5;z(1-2z)=6+6(4z-3)

Solution for z=0.5;z(1-2z)=6+6(4z-3) equation:

z=0.5z(1-2z)=6+6(4z-3)

We move all terms to the left:

z-(0.5z(1-2z))=0

We add all the numbers together, and all the variables

z-(0.5z(-2z+1))=0


We calculate terms in parentheses: -(0.5z(-2z+1)), so:

0.5z(-2z+1)

We multiply parentheses

0z^2+0z

We add all the numbers together, and all the variables

z^2+z

Back to the equation:

-(z^2+z)


We get rid of parentheses

-z^2+z-z=0

We add all the numbers together, and all the variables

-1z^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{-2}=0$