z=2(4z-28)

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Solution for z=2(4z-28) equation: 



z=2(4z-28)

We move all terms to the left:

z-(2(4z-28))=0



We calculate terms in parentheses: -(2(4z-28)), so:

2(4z-28)

We multiply parentheses

8z-56

Back to the equation:

-(8z-56)



We get rid of parentheses

z-8z+56=0

We add all the numbers together, and all the variables

-7z+56=0

We move all terms containing z to the left, all other terms to the right

-7z=-56

z=-56/-7

z=+8

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