z=2(z-2)

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Solution for z=2(z-2) equation: 



z=2(z-2)

We move all terms to the left:

z-(2(z-2))=0



We calculate terms in parentheses: -(2(z-2)), so:

2(z-2)

We multiply parentheses

2z-4

Back to the equation:

-(2z-4)



We get rid of parentheses

z-2z+4=0

We add all the numbers together, and all the variables

-1z+4=0

We move all terms containing z to the left, all other terms to the right

-z=-4

z=-4/-1

z=+4

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