z=2/3i

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Solution for z=2/3i equation: 


x in (-oo:+oo)

z = (2/3)*i // - (2/3)*i

z-((2/3)*i) = 0

(-2/3)*i+z = 0

z-2/3*i = 0

x należy do R

x in (-oo:+oo)

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