z=4(2z+3)=15

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Solution for z=4(2z+3)=15 equation: 



z=4(2z+3)=15

We move all terms to the left:

z-(4(2z+3))=0



We calculate terms in parentheses: -(4(2z+3)), so:

4(2z+3)

We multiply parentheses

8z+12

Back to the equation:

-(8z+12)



We get rid of parentheses

z-8z-12=0

We add all the numbers together, and all the variables

-7z-12=0

We move all terms containing z to the left, all other terms to the right

-7z=12

z=12/-7

z=-1+5/7

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